Base | Representation |
---|---|
bin | 111110011010111100… |
… | …0101010110100110111 |
3 | 110211000001000200110211 |
4 | 1330311320222310313 |
5 | 4144012244042403 |
6 | 141325242330251 |
7 | 12453556330024 |
oct | 1746570526467 |
9 | 424001020424 |
10 | 134048034103 |
11 | 51938691065 |
12 | 21b904b9987 |
13 | c843743899 |
14 | 66b8d6454b |
15 | 374842606d |
hex | 1f35e2ad37 |
134048034103 has 2 divisors, whose sum is σ = 134048034104. Its totient is φ = 134048034102.
The previous prime is 134048034101. The next prime is 134048034119. The reversal of 134048034103 is 301430840431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134048034103 - 21 = 134048034101 is a prime.
Together with 134048034101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134048034101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67024017051 + 67024017052.
It is an arithmetic number, because the mean of its divisors is an integer number (67024017052).
Almost surely, 2134048034103 is an apocalyptic number.
134048034103 is a deficient number, since it is larger than the sum of its proper divisors (1).
134048034103 is an equidigital number, since it uses as much as digits as its factorization.
134048034103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 134048034103 its reverse (301430840431), we get a palindrome (435478874534).
The spelling of 134048034103 in words is "one hundred thirty-four billion, forty-eight million, thirty-four thousand, one hundred three".
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