Base | Representation |
---|---|
bin | 111110011010111100… |
… | …0101010110101000111 |
3 | 110211000001000200111102 |
4 | 1330311320222311013 |
5 | 4144012244042434 |
6 | 141325242330315 |
7 | 12453556330046 |
oct | 1746570526507 |
9 | 424001020442 |
10 | 134048034119 |
11 | 5193869107a |
12 | 21b904b999b |
13 | c8437438ac |
14 | 66b8d6455d |
15 | 374842607e |
hex | 1f35e2ad47 |
134048034119 has 2 divisors, whose sum is σ = 134048034120. Its totient is φ = 134048034118.
The previous prime is 134048034103. The next prime is 134048034173. The reversal of 134048034119 is 911430840431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134048034119 - 24 = 134048034103 is a prime.
It is a super-2 number, since 2×1340480341192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134048034199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67024017059 + 67024017060.
It is an arithmetic number, because the mean of its divisors is an integer number (67024017060).
Almost surely, 2134048034119 is an apocalyptic number.
134048034119 is a deficient number, since it is larger than the sum of its proper divisors (1).
134048034119 is an equidigital number, since it uses as much as digits as its factorization.
134048034119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 38.
The spelling of 134048034119 in words is "one hundred thirty-four billion, forty-eight million, thirty-four thousand, one hundred nineteen".
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