Base | Representation |
---|---|
bin | 1100001100010011000101… |
… | …1011100101010010011111 |
3 | 1202110112201220222111010001 |
4 | 3003010301123211102133 |
5 | 3224113301043320043 |
6 | 44302211014155131 |
7 | 2552336601001054 |
oct | 303046133452237 |
9 | 52415656874101 |
10 | 13405422245023 |
11 | 42a9231419026 |
12 | 1606088952aa7 |
13 | 763183784b63 |
14 | 344b7c3a102b |
15 | 183a8c0e174d |
hex | c31316e549f |
13405422245023 has 2 divisors, whose sum is σ = 13405422245024. Its totient is φ = 13405422245022.
The previous prime is 13405422244999. The next prime is 13405422245063. The reversal of 13405422245023 is 32054222450431.
It is a happy number.
13405422245023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13405422245023 - 213 = 13405422236831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405422245063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702711122511 + 6702711122512.
It is an arithmetic number, because the mean of its divisors is an integer number (6702711122512).
Almost surely, 213405422245023 is an apocalyptic number.
13405422245023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405422245023 is an equidigital number, since it uses as much as digits as its factorization.
13405422245023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 13405422245023 its reverse (32054222450431), we get a palindrome (45459644695454).
The spelling of 13405422245023 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, two hundred forty-five thousand, twenty-three".
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