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13405422245023 is a prime number
BaseRepresentation
bin1100001100010011000101…
…1011100101010010011111
31202110112201220222111010001
43003010301123211102133
53224113301043320043
644302211014155131
72552336601001054
oct303046133452237
952415656874101
1013405422245023
1142a9231419026
121606088952aa7
13763183784b63
14344b7c3a102b
15183a8c0e174d
hexc31316e549f

13405422245023 has 2 divisors, whose sum is σ = 13405422245024. Its totient is φ = 13405422245022.

The previous prime is 13405422244999. The next prime is 13405422245063. The reversal of 13405422245023 is 32054222450431.

It is a happy number.

13405422245023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13405422245023 - 213 = 13405422236831 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13405422245063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702711122511 + 6702711122512.

It is an arithmetic number, because the mean of its divisors is an integer number (6702711122512).

Almost surely, 213405422245023 is an apocalyptic number.

13405422245023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405422245023 is an equidigital number, since it uses as much as digits as its factorization.

13405422245023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 37.

Adding to 13405422245023 its reverse (32054222450431), we get a palindrome (45459644695454).

The spelling of 13405422245023 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, two hundred forty-five thousand, twenty-three".