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13405422245050 = 2521124373494991
BaseRepresentation
bin1100001100010011000101…
…1011100101010010111010
31202110112201220222111011001
43003010301123211102322
53224113301043320200
644302211014155214
72552336601001123
oct303046133452272
952415656874131
1013405422245050
1142a9231419050
121606088952b0a
13763183784b84
14344b7c3a104a
15183a8c0e176a
hexc31316e54ba

13405422245050 has 24 divisors (see below), whose sum is σ = 27200820411072. Its totient is φ = 4874698998000.

The previous prime is 13405422245023. The next prime is 13405422245063. The reversal of 13405422245050 is 5054222450431.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12186746946 + ... + 12186748045.

It is an arithmetic number, because the mean of its divisors is an integer number (1133367517128).

Almost surely, 213405422245050 is an apocalyptic number.

13405422245050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13405422245050 is an abundant number, since it is smaller than the sum of its proper divisors (13795398166022).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13405422245050 is a wasteful number, since it uses less digits than its factorization.

13405422245050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24373495014 (or 24373495009 counting only the distinct ones).

The product of its (nonzero) digits is 192000, while the sum is 37.

Adding to 13405422245050 its reverse (5054222450431), we get a palindrome (18459644695481).

The spelling of 13405422245050 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, two hundred forty-five thousand, fifty".

Divisors: 1 2 5 10 11 22 25 50 55 110 275 550 24373494991 48746989982 121867474955 243734949910 268108444901 536216889802 609337374775 1218674749550 1340542224505 2681084449010 6702711122525 13405422245050