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1340667040151 is a prime number
BaseRepresentation
bin10011100000100101111…
…110111001000110010111
311202011111101120010210102
4103200211332321012113
5133431141230241101
62503521031244315
7165600656546555
oct23404576710627
94664441503712
101340667040151
1147763465838a
121979b681969b
1399569418aca
1448c62590bd5
1524d1926d86b
hex13825fb9197

1340667040151 has 2 divisors, whose sum is σ = 1340667040152. Its totient is φ = 1340667040150.

The previous prime is 1340667040147. The next prime is 1340667040169. The reversal of 1340667040151 is 1510407660431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1510407660431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340667040151 - 22 = 1340667040147 is a prime.

It is a super-2 number, since 2×13406670401512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340667040121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670333520075 + 670333520076.

It is an arithmetic number, because the mean of its divisors is an integer number (670333520076).

Almost surely, 21340667040151 is an apocalyptic number.

1340667040151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340667040151 is an equidigital number, since it uses as much as digits as its factorization.

1340667040151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 38.

The spelling of 1340667040151 in words is "one trillion, three hundred forty billion, six hundred sixty-seven million, forty thousand, one hundred fifty-one".