Search a number
-
+
134073145543 is a prime number
BaseRepresentation
bin111110011011101100…
…0011101100011000111
3110211001210021110220011
41330313120131203013
54144040211124133
6141331540451051
712454312635151
oct1746730354307
9424053243804
10134073145543
1151950882717
1221b989a9a87
13c8489c671c
1466bc41dad1
15374a7366cd
hex1f3761d8c7

134073145543 has 2 divisors, whose sum is σ = 134073145544. Its totient is φ = 134073145542.

The previous prime is 134073145541. The next prime is 134073145601. The reversal of 134073145543 is 345541370431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (345541370431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134073145543 - 21 = 134073145541 is a prime.

Together with 134073145541, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 134073145496 and 134073145505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134073145541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67036572771 + 67036572772.

It is an arithmetic number, because the mean of its divisors is an integer number (67036572772).

Almost surely, 2134073145543 is an apocalyptic number.

134073145543 is a deficient number, since it is larger than the sum of its proper divisors (1).

134073145543 is an equidigital number, since it uses as much as digits as its factorization.

134073145543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 40.

The spelling of 134073145543 in words is "one hundred thirty-four billion, seventy-three million, one hundred forty-five thousand, five hundred forty-three".