Base | Representation |
---|---|
bin | 111110011011101100… |
… | …0011101100011000111 |
3 | 110211001210021110220011 |
4 | 1330313120131203013 |
5 | 4144040211124133 |
6 | 141331540451051 |
7 | 12454312635151 |
oct | 1746730354307 |
9 | 424053243804 |
10 | 134073145543 |
11 | 51950882717 |
12 | 21b989a9a87 |
13 | c8489c671c |
14 | 66bc41dad1 |
15 | 374a7366cd |
hex | 1f3761d8c7 |
134073145543 has 2 divisors, whose sum is σ = 134073145544. Its totient is φ = 134073145542.
The previous prime is 134073145541. The next prime is 134073145601. The reversal of 134073145543 is 345541370431.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (345541370431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134073145543 - 21 = 134073145541 is a prime.
Together with 134073145541, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 134073145496 and 134073145505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134073145541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67036572771 + 67036572772.
It is an arithmetic number, because the mean of its divisors is an integer number (67036572772).
Almost surely, 2134073145543 is an apocalyptic number.
134073145543 is a deficient number, since it is larger than the sum of its proper divisors (1).
134073145543 is an equidigital number, since it uses as much as digits as its factorization.
134073145543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 40.
The spelling of 134073145543 in words is "one hundred thirty-four billion, seventy-three million, one hundred forty-five thousand, five hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •