Base | Representation |
---|---|
bin | 1100001100100101101110… |
… | …0101101110000000100110 |
3 | 1202111000122112122000010201 |
4 | 3003021123211232000212 |
5 | 3224204022133400200 |
6 | 44304355230141114 |
7 | 2552604551401312 |
oct | 303113345560046 |
9 | 52430575560121 |
10 | 13410424512550 |
11 | 430036903471a |
12 | 160704405179a |
13 | 76379cc28880 |
14 | 3450d4892b42 |
15 | 183c81344c6a |
hex | c325b96e026 |
13410424512550 has 48 divisors (see below), whose sum is σ = 28275907257360. Its totient is φ = 4690933914240.
The previous prime is 13410424512481. The next prime is 13410424512587. The reversal of 13410424512550 is 5521542401431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 542919817 + ... + 542944516.
It is an arithmetic number, because the mean of its divisors is an integer number (589081401195).
Almost surely, 213410424512550 is an apocalyptic number.
13410424512550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13410424512550 is an abundant number, since it is smaller than the sum of its proper divisors (14865482744810).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13410424512550 is a wasteful number, since it uses less digits than its factorization.
13410424512550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1085864377 (or 1085864372 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 13410424512550 its reverse (5521542401431), we get a palindrome (18931966913981).
The spelling of 13410424512550 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-four million, five hundred twelve thousand, five hundred fifty".
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