Base | Representation |
---|---|
bin | 100111111110000… |
… | …0000100100100111 |
3 | 10110110120111221021 |
4 | 1033330000210213 |
5 | 10221312143142 |
6 | 341025032011 |
7 | 45143266024 |
oct | 11774004447 |
9 | 3413514837 |
10 | 1341131047 |
11 | 629040673 |
12 | 315185607 |
13 | 184b09589 |
14 | ca18a54b |
15 | 7cb17267 |
hex | 4ff00927 |
1341131047 has 2 divisors, whose sum is σ = 1341131048. Its totient is φ = 1341131046.
The previous prime is 1341131009. The next prime is 1341131089. The reversal of 1341131047 is 7401311431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1341131047 - 27 = 1341130919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341131647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670565523 + 670565524.
It is an arithmetic number, because the mean of its divisors is an integer number (670565524).
Almost surely, 21341131047 is an apocalyptic number.
1341131047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341131047 is an equidigital number, since it uses as much as digits as its factorization.
1341131047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
The square root of 1341131047 is about 36621.4561015807. The cubic root of 1341131047 is about 1102.7838706987.
Adding to 1341131047 its reverse (7401311431), we get a palindrome (8742442478).
The spelling of 1341131047 in words is "one billion, three hundred forty-one million, one hundred thirty-one thousand, forty-seven".
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