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13411426340551 is a prime number
BaseRepresentation
bin1100001100101001011101…
…0011011000111011000111
31202111010020100202010210111
43003022113103120323013
53224213100120344201
644305042454533451
72552641434654541
oct303122723307307
952433210663714
1013411426340551
114300832596948
121607283667287
137638cc655ac5
1434518b958691
15183cde287b51
hexc32974d8ec7

13411426340551 has 2 divisors, whose sum is σ = 13411426340552. Its totient is φ = 13411426340550.

The previous prime is 13411426340539. The next prime is 13411426340567. The reversal of 13411426340551 is 15504362411431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13411426340551 - 211 = 13411426338503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13411426340581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705713170275 + 6705713170276.

It is an arithmetic number, because the mean of its divisors is an integer number (6705713170276).

Almost surely, 213411426340551 is an apocalyptic number.

13411426340551 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411426340551 is an equidigital number, since it uses as much as digits as its factorization.

13411426340551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 40.

Adding to 13411426340551 its reverse (15504362411431), we get a palindrome (28915788751982).

The spelling of 13411426340551 in words is "thirteen trillion, four hundred eleven billion, four hundred twenty-six million, three hundred forty thousand, five hundred fifty-one".