Base | Representation |
---|---|
bin | 1100001100101001011101… |
… | …0011011000111011000111 |
3 | 1202111010020100202010210111 |
4 | 3003022113103120323013 |
5 | 3224213100120344201 |
6 | 44305042454533451 |
7 | 2552641434654541 |
oct | 303122723307307 |
9 | 52433210663714 |
10 | 13411426340551 |
11 | 4300832596948 |
12 | 1607283667287 |
13 | 7638cc655ac5 |
14 | 34518b958691 |
15 | 183cde287b51 |
hex | c32974d8ec7 |
13411426340551 has 2 divisors, whose sum is σ = 13411426340552. Its totient is φ = 13411426340550.
The previous prime is 13411426340539. The next prime is 13411426340567. The reversal of 13411426340551 is 15504362411431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411426340551 - 211 = 13411426338503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411426340581) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705713170275 + 6705713170276.
It is an arithmetic number, because the mean of its divisors is an integer number (6705713170276).
Almost surely, 213411426340551 is an apocalyptic number.
13411426340551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411426340551 is an equidigital number, since it uses as much as digits as its factorization.
13411426340551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 40.
Adding to 13411426340551 its reverse (15504362411431), we get a palindrome (28915788751982).
The spelling of 13411426340551 in words is "thirteen trillion, four hundred eleven billion, four hundred twenty-six million, three hundred forty thousand, five hundred fifty-one".
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