Base | Representation |
---|---|
bin | 1100001100101001011101… |
… | …0011011000111011010111 |
3 | 1202111010020100202010211002 |
4 | 3003022113103120323113 |
5 | 3224213100120344232 |
6 | 44305042454533515 |
7 | 2552641434654563 |
oct | 303122723307327 |
9 | 52433210663732 |
10 | 13411426340567 |
11 | 4300832596962 |
12 | 160728366729b |
13 | 7638cc655b08 |
14 | 34518b9586a3 |
15 | 183cde287b62 |
hex | c32974d8ed7 |
13411426340567 has 2 divisors, whose sum is σ = 13411426340568. Its totient is φ = 13411426340566.
The previous prime is 13411426340551. The next prime is 13411426340581. The reversal of 13411426340567 is 76504362411431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13411426340567 - 24 = 13411426340551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411426340527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705713170283 + 6705713170284.
It is an arithmetic number, because the mean of its divisors is an integer number (6705713170284).
Almost surely, 213411426340567 is an apocalyptic number.
13411426340567 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411426340567 is an equidigital number, since it uses as much as digits as its factorization.
13411426340567 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 47.
Adding to 13411426340567 its reverse (76504362411431), we get a palindrome (89915788751998).
The spelling of 13411426340567 in words is "thirteen trillion, four hundred eleven billion, four hundred twenty-six million, three hundred forty thousand, five hundred sixty-seven".
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