13411426340550 has 48 divisors (see below), whose sum is σ = 38011814088192. Its totient is φ = 3065468877600.

The previous prime is 13411426340539. The next prime is 13411426340551. The reversal of 13411426340550 is 5504362411431.

13411426340550 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13411426340499 and 13411426340508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411426340551) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6386392446 + ... + 6386394545.

It is an arithmetic number, because the mean of its divisors is an integer number (791912793504).

Almost surely, 2^{13411426340550} is an apocalyptic number.

13411426340550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13411426340550 is an abundant number, since it is smaller than the sum of its proper divisors (24600387747642).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13411426340550 is a wasteful number, since it uses less digits than its factorization.

13411426340550 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12772787013 (or 12772787008 counting only the distinct ones).

The product of its (nonzero) digits is 172800, while the sum is 39.

Adding to 13411426340550 its reverse (5504362411431), we get a palindrome (18915788751981).

The spelling of 13411426340550 in words is "thirteen trillion, four hundred eleven billion, four hundred twenty-six million, three hundred forty thousand, five hundred fifty".