13414041001213 has 2 divisors, whose sum is σ = 13414041001214. Its totient is φ = 13414041001212.

The previous prime is 13414041001211. The next prime is 13414041001279. The reversal of 13414041001213 is 31210014041431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9721655853849 + 3692385147364 = 3117957^2 + 1921558^2 .

It is a cyclic number.

It is not a de Polignac number, because 13414041001213 - 2¹ = 13414041001211 is a prime.

Together with 13414041001211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13414041001211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707020500606 + 6707020500607.

It is an arithmetic number, because the mean of its divisors is an integer number (6707020500607).

Almost surely, 2^{13414041001213} is an apocalyptic number.

It is an amenable number.

13414041001213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414041001213 is an equidigital number, since it uses as much as digits as its factorization.

13414041001213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13414041001213 its reverse (31210014041431), we get a palindrome (44624055042644).

The spelling of 13414041001213 in words is "thirteen trillion, four hundred fourteen billion, forty-one million, one thousand, two hundred thirteen".