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134206727 is a prime number
BaseRepresentation
bin1111111111111…
…01010100000111
3100100112102000112
413333331110013
5233324103402
621152303235
73216511154
oct777752407
9310472015
10134206727
1169835556
1238b41b1b
1321a5c485
1413b7722b
15bbaee52
hex7ffd507

134206727 has 2 divisors, whose sum is σ = 134206728. Its totient is φ = 134206726.

The previous prime is 134206697. The next prime is 134206729. The reversal of 134206727 is 727602431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134206727 is a prime.

It is a super-2 number, since 2×1342067272 = 36022891144105058, which contains 22 as substring.

Together with 134206729, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p7602971 and since 134206727 and 7602971 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 134206693 and 134206702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134206729) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67103363 + 67103364.

It is an arithmetic number, because the mean of its divisors is an integer number (67103364).

Almost surely, 2134206727 is an apocalyptic number.

134206727 is a deficient number, since it is larger than the sum of its proper divisors (1).

134206727 is an equidigital number, since it uses as much as digits as its factorization.

134206727 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14112, while the sum is 32.

The square root of 134206727 is about 11584.7627079712. The cubic root of 134206727 is about 511.9860111229.

The spelling of 134206727 in words is "one hundred thirty-four million, two hundred six thousand, seven hundred twenty-seven".