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134214451200 = 21733523741
BaseRepresentation
bin111110011111111001…
…1100000000000000000
3110211102122011112211000
41330333303200000000
54144332344414300
6141353545252000
712460650004044
oct1747763400000
9424378145730
10134214451200
1151a13616755
1222018194000
13c86c07013b
1466d30c4024
153757d49c00
hex1f3fce0000

134214451200 has 864 divisors, whose sum is σ = 518791482720. Its totient is φ = 33973862400.

The previous prime is 134214451169. The next prime is 134214451211. The reversal of 134214451200 is 2154412431.

134214451200 is a `hidden beast` number, since 1 + 3 + 4 + 2 + 1 + 4 + 451 + 200 = 666.

It is a tau number, because it is divible by the number of its divisors (864).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a zygodrome in base 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3273523180 + ... + 3273523220.

It is an arithmetic number, because the mean of its divisors is an integer number (600453105).

Almost surely, 2134214451200 is an apocalyptic number.

134214451200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134214451200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (259395741360).

134214451200 is an abundant number, since it is smaller than the sum of its proper divisors (384577031520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134214451200 is an frugal number, since it uses more digits than its factorization.

134214451200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131 (or 88 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 27.

Adding to 134214451200 its reverse (2154412431), we get a palindrome (136368863631).

The spelling of 134214451200 in words is "one hundred thirty-four billion, two hundred fourteen million, four hundred fifty-one thousand, two hundred".