Base | Representation |
---|---|
bin | 10011100010001001010… |
… | …100011011111001100111 |
3 | 11202022210112112210011021 |
4 | 103202021110123321213 |
5 | 133443044402211403 |
6 | 2504354244152011 |
7 | 165660164420332 |
oct | 23421124337147 |
9 | 4668715483137 |
10 | 1342333632103 |
11 | 47830a382602 |
12 | 1981a0998607 |
13 | 997737990a9 |
14 | 48d7da5b619 |
15 | 24db57238bd |
hex | 1388951be67 |
1342333632103 has 2 divisors, whose sum is σ = 1342333632104. Its totient is φ = 1342333632102.
The previous prime is 1342333632049. The next prime is 1342333632137. The reversal of 1342333632103 is 3012363332431.
It is an a-pointer prime, because the next prime (1342333632137) can be obtained adding 1342333632103 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1342333632103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342333692103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671166816051 + 671166816052.
It is an arithmetic number, because the mean of its divisors is an integer number (671166816052).
Almost surely, 21342333632103 is an apocalyptic number.
1342333632103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342333632103 is an equidigital number, since it uses as much as digits as its factorization.
1342333632103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 34.
Adding to 1342333632103 its reverse (3012363332431), we get a palindrome (4354696964534).
The spelling of 1342333632103 in words is "one trillion, three hundred forty-two billion, three hundred thirty-three million, six hundred thirty-two thousand, one hundred three".
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