Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …1000111111011100001111 |
3 | 1202112110100220012011010102 |
4 | 3003113121220333130033 |
5 | 3224430232043421422 |
6 | 44315315453401315 |
7 | 2553645345553664 |
oct | 303273150773417 |
9 | 52473326164112 |
10 | 13425424201487 |
11 | 4306765a63a61 |
12 | 1609b2b49923b |
13 | 76502069615c |
14 | 345b18a35a6b |
15 | 18435d0e7192 |
hex | c35d9a3f70f |
13425424201487 has 2 divisors, whose sum is σ = 13425424201488. Its totient is φ = 13425424201486.
The previous prime is 13425424201363. The next prime is 13425424201489. The reversal of 13425424201487 is 78410242452431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13425424201487 - 234 = 13408244332303 is a prime.
It is a super-2 number, since 2×134254242014872 (a number of 27 digits) contains 22 as substring.
Together with 13425424201489, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13425424201489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712712100743 + 6712712100744.
It is an arithmetic number, because the mean of its divisors is an integer number (6712712100744).
Almost surely, 213425424201487 is an apocalyptic number.
13425424201487 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425424201487 is an equidigital number, since it uses as much as digits as its factorization.
13425424201487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1720320, while the sum is 47.
The spelling of 13425424201487 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-four million, two hundred one thousand, four hundred eighty-seven".
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