13426544101541 has 2 divisors, whose sum is σ = 13426544101542. Its totient is φ = 13426544101540.

The previous prime is 13426544101489. The next prime is 13426544101543. The reversal of 13426544101541 is 14510144562431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11783058561316 + 1643485540225 = 3432646^2 + 1281985^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13426544101541 is a prime.

Together with 13426544101543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13426544101543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6713272050770 + 6713272050771.

It is an arithmetic number, because the mean of its divisors is an integer number (6713272050771).

Almost surely, 2^{13426544101541} is an apocalyptic number.

It is an amenable number.

13426544101541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13426544101541 is an equidigital number, since it uses as much as digits as its factorization.

13426544101541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 41.

Adding to 13426544101541 its reverse (14510144562431), we get a palindrome (27936688663972).

The spelling of 13426544101541 in words is "thirteen trillion, four hundred twenty-six billion, five hundred forty-four million, one hundred one thousand, five hundred forty-one".