Base | Representation |
---|---|
bin | 1100001101101110110110… |
… | …0111111111110011000101 |
3 | 1202112220022120211021022202 |
4 | 3003123231213333303011 |
5 | 3230014222414434141 |
6 | 44321403140004245 |
7 | 2554201161211565 |
oct | 303335547776305 |
9 | 52486276737282 |
10 | 13430054452421 |
11 | 4308721688022 |
12 | 160aa02090685 |
13 | 7655aaa456c9 |
14 | 346037968da5 |
15 | 18452e86349b |
hex | c36ed9ffcc5 |
13430054452421 has 2 divisors, whose sum is σ = 13430054452422. Its totient is φ = 13430054452420.
The previous prime is 13430054452351. The next prime is 13430054452459. The reversal of 13430054452421 is 12425445003431.
It is an a-pointer prime, because the next prime (13430054452459) can be obtained adding 13430054452421 to its sum of digits (38).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13386744264100 + 43310188321 = 3658790^2 + 208111^2 .
It is an emirp because it is prime and its reverse (12425445003431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13430054452421 is a prime.
It is a super-2 number, since 2×134300544524212 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13430054452481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715027226210 + 6715027226211.
It is an arithmetic number, because the mean of its divisors is an integer number (6715027226211).
Almost surely, 213430054452421 is an apocalyptic number.
It is an amenable number.
13430054452421 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430054452421 is an equidigital number, since it uses as much as digits as its factorization.
13430054452421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 13430054452421 its reverse (12425445003431), we get a palindrome (25855499455852).
The spelling of 13430054452421 in words is "thirteen trillion, four hundred thirty billion, fifty-four million, four hundred fifty-two thousand, four hundred twenty-one".
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