Base | Representation |
---|---|
bin | 11110100010100111010000… |
… | …100010110101101000010100 |
3 | 122121120212102111221020111212 |
4 | 132202213100202311220110 |
5 | 120101144340311310200 |
6 | 1153401432231120552 |
7 | 40202205042531440 |
oct | 3642472042655024 |
9 | 577525374836455 |
10 | 134320011041300 |
11 | 39886884576657 |
12 | 1309414bb13158 |
13 | 59c4426c51956 |
14 | 25251a219b820 |
15 | 107de89910035 |
hex | 7a29d08b5a14 |
134320011041300 has 144 divisors (see below), whose sum is σ = 336581737390080. Its totient is φ = 45573735162240.
The previous prime is 134320011041299. The next prime is 134320011041329. The reversal of 134320011041300 is 3140110023431.
It is a super-2 number, since 2×1343200110413002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 103104587 + ... + 104399213.
It is an arithmetic number, because the mean of its divisors is an integer number (2337373176320).
Almost surely, 2134320011041300 is an apocalyptic number.
134320011041300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134320011041300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168290868695040).
134320011041300 is an abundant number, since it is smaller than the sum of its proper divisors (202261726348780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134320011041300 is a wasteful number, since it uses less digits than its factorization.
134320011041300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1296190 (or 1296183 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 134320011041300 its reverse (3140110023431), we get a palindrome (137460121064731).
The spelling of 134320011041300 in words is "one hundred thirty-four trillion, three hundred twenty billion, eleven million, forty-one thousand, three hundred".
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