Base | Representation |
---|---|
bin | 111110100011000101… |
… | …1101100000000010111 |
3 | 110211201002111220121102 |
4 | 1331012023230000113 |
5 | 4200042243031002 |
6 | 141412330540315 |
7 | 12463416346616 |
oct | 1750613540027 |
9 | 424632456542 |
10 | 134321455127 |
11 | 51a68a61352 |
12 | 22047b9769b |
13 | c888296882 |
14 | 67033b987d |
15 | 3762434a02 |
hex | 1f462ec017 |
134321455127 has 2 divisors, whose sum is σ = 134321455128. Its totient is φ = 134321455126.
The previous prime is 134321455039. The next prime is 134321455129. The reversal of 134321455127 is 721554123431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134321455127 - 228 = 134053019671 is a prime.
It is a super-2 number, since 2×1343214551272 (a number of 23 digits) contains 22 as substring.
Together with 134321455129, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134321455129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67160727563 + 67160727564.
It is an arithmetic number, because the mean of its divisors is an integer number (67160727564).
Almost surely, 2134321455127 is an apocalyptic number.
134321455127 is a deficient number, since it is larger than the sum of its proper divisors (1).
134321455127 is an equidigital number, since it uses as much as digits as its factorization.
134321455127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100800, while the sum is 38.
Adding to 134321455127 its reverse (721554123431), we get a palindrome (855875578558).
The spelling of 134321455127 in words is "one hundred thirty-four billion, three hundred twenty-one million, four hundred fifty-five thousand, one hundred twenty-seven".
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