Base | Representation |
---|---|
bin | 1100001101110111101010… |
… | …1100001111001001110110 |
3 | 1202120010102112012000220122 |
4 | 3003131322230033021312 |
5 | 3230034044303320400 |
6 | 44322434042331542 |
7 | 2554313626630505 |
oct | 303357254171166 |
9 | 52503375160818 |
10 | 13432421151350 |
11 | 4309726614a53 |
12 | 160b3627b9bb2 |
13 | 765897171986 |
14 | 3461bddda83c |
15 | 18461c50c685 |
hex | c377ab0f276 |
13432421151350 has 24 divisors (see below), whose sum is σ = 25087972672488. Its totient is φ = 5350673980800.
The previous prime is 13432421151307. The next prime is 13432421151421. The reversal of 13432421151350 is 5315112423431.
It is a self number, because there is not a number n which added to its sum of digits gives 13432421151350.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 557349824 + ... + 557373923.
It is an arithmetic number, because the mean of its divisors is an integer number (1045332194687).
Almost surely, 213432421151350 is an apocalyptic number.
13432421151350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13432421151350 is a deficient number, since it is larger than the sum of its proper divisors (11655551521138).
13432421151350 is a wasteful number, since it uses less digits than its factorization.
13432421151350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1114724000 (or 1114723995 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13432421151350 its reverse (5315112423431), we get a palindrome (18747533574781).
The spelling of 13432421151350 in words is "thirteen trillion, four hundred thirty-two billion, four hundred twenty-one million, one hundred fifty-one thousand, three hundred fifty".
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