1343311100 has 72 divisors (see below), whose sum is σ = 3107488608. Its totient is φ = 502272000.

The previous prime is 1343311097. The next prime is 1343311141. The reversal of 1343311100 is 11133431.

It is a super-2 number, since 2×1343311100² = 3608969422766420000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 254084 + ... + 259316.

It is an arithmetic number, because the mean of its divisors is an integer number (43159564).

Almost surely, 2^1343311100 is an apocalyptic number.

1343311100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1343311100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1553744304).

1343311100 is an abundant number, since it is smaller than the sum of its proper divisors (1764177508).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1343311100 is a wasteful number, since it uses less digits than its factorization.

1343311100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5415 (or 5408 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1343311100 is about 36651.2087113099. The cubic root of 1343311100 is about 1103.3810844716.

Adding to 1343311100 its reverse (11133431), we get a palindrome (1354444531).

The spelling of 1343311100 in words is "one billion, three hundred forty-three million, three hundred eleven thousand, one hundred".