Base | Representation |
---|---|
bin | 10011100011000101100… |
… | …011100110100110010100 |
3 | 11202102101222012001000001 |
4 | 103203011203212212110 |
5 | 134002132111203134 |
6 | 2505042425101044 |
7 | 166024215435151 |
oct | 23430543464624 |
9 | 4672358161001 |
10 | 1343344241044 |
11 | 478788892003 |
12 | 198423327784 |
13 | 998a4c7c050 |
14 | 49037d6b228 |
15 | 24e242ed414 |
hex | 138c58e6994 |
1343344241044 has 96 divisors (see below), whose sum is σ = 2737828195200. Its totient is φ = 571389603840.
The previous prime is 1343344241011. The next prime is 1343344241051. The reversal of 1343344241044 is 4401424433431.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1343344240994 and 1343344241012.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14008492 + ... + 14104060.
It is an arithmetic number, because the mean of its divisors is an integer number (28519043700).
Almost surely, 21343344241044 is an apocalyptic number.
It is an amenable number.
1343344241044 is an abundant number, since it is smaller than the sum of its proper divisors (1394483954156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1343344241044 is a wasteful number, since it uses less digits than its factorization.
1343344241044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95993 (or 95991 counting only the distinct ones).
The product of its (nonzero) digits is 221184, while the sum is 37.
Adding to 1343344241044 its reverse (4401424433431), we get a palindrome (5744768674475).
The spelling of 1343344241044 in words is "one trillion, three hundred forty-three billion, three hundred forty-four million, two hundred forty-one thousand, forty-four".
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