Base | Representation |
---|---|
bin | 1100001101111111001110… |
… | …1100010011001100101010 |
3 | 1202120022200000002202021221 |
4 | 3003133303230103030222 |
5 | 3230102224002223200 |
6 | 44323411321452254 |
7 | 2554415140100062 |
oct | 303376354231452 |
9 | 52508600082257 |
10 | 13434451211050 |
11 | 430a578522941 |
12 | 160b82a64108a |
13 | 765b2b91222c |
14 | 34633387c3a2 |
15 | 1846da85b91a |
hex | c37f3b1332a |
13434451211050 has 24 divisors (see below), whose sum is σ = 24988186144800. Its totient is φ = 5373757496880.
The previous prime is 13434451211021. The next prime is 13434451211063. The reversal of 13434451211050 is 5011215443431.
It is a junction number, because it is equal to n+sod(n) for n = 13434451210997 and 13434451211015.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15915531 + ... + 16738369.
It is an arithmetic number, because the mean of its divisors is an integer number (1041174422700).
Almost surely, 213434451211050 is an apocalyptic number.
13434451211050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13434451211050 is a deficient number, since it is larger than the sum of its proper divisors (11553734933750).
13434451211050 is a wasteful number, since it uses less digits than its factorization.
13434451211050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1149390 (or 1149385 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 13434451211050 its reverse (5011215443431), we get a palindrome (18445666654481).
The spelling of 13434451211050 in words is "thirteen trillion, four hundred thirty-four billion, four hundred fifty-one million, two hundred eleven thousand, fifty".
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