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13437997253 is a prime number
BaseRepresentation
bin11001000001111011…
…11001000011000101
31021200111221222201222
430200331321003011
5210010111403003
610101234530125
7654002043362
oct144075710305
937614858658
1013437997253
11577644325a
122730436945
131362058385
149169c1469
15539b1dc38
hex320f790c5

13437997253 has 2 divisors, whose sum is σ = 13437997254. Its totient is φ = 13437997252.

The previous prime is 13437997229. The next prime is 13437997277. The reversal of 13437997253 is 35279973431.

It is a balanced prime because it is at equal distance from previous prime (13437997229) and next prime (13437997277).

It can be written as a sum of positive squares in only one way, i.e., 7450797124 + 5987200129 = 86318^2 + 77377^2 .

It is an emirp because it is prime and its reverse (35279973431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13437997253 - 224 = 13421220037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13437997195 and 13437997204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13437997283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6718998626 + 6718998627.

It is an arithmetic number, because the mean of its divisors is an integer number (6718998627).

Almost surely, 213437997253 is an apocalyptic number.

It is an amenable number.

13437997253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13437997253 is an equidigital number, since it uses as much as digits as its factorization.

13437997253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4286520, while the sum is 53.

The spelling of 13437997253 in words is "thirteen billion, four hundred thirty-seven million, nine hundred ninety-seven thousand, two hundred fifty-three".