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134401104430 = 2515785605799
BaseRepresentation
bin111110100101011101…
…1100001101000101110
3110211220122101111220121
41331022323201220232
54200223140320210
6141424254035154
712465404352415
oct1751273415056
9424818344817
10134401104430
1151aa9a1301a
122206a7a8aba
13c89b933438
14670dbd047c
1537694196da
hex1f4aee1a2e

134401104430 has 16 divisors (see below), whose sum is σ = 243462895200. Its totient is φ = 53418017952.

The previous prime is 134401104419. The next prime is 134401104433. The reversal of 134401104430 is 34401104431.

It is a junction number, because it is equal to n+sod(n) for n = 134401104395 and 134401104404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134401104433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42801330 + ... + 42804469.

It is an arithmetic number, because the mean of its divisors is an integer number (15216430950).

Almost surely, 2134401104430 is an apocalyptic number.

134401104430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134401104430 is a deficient number, since it is larger than the sum of its proper divisors (109061790770).

134401104430 is a wasteful number, since it uses less digits than its factorization.

134401104430 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85605963.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 134401104430 its reverse (34401104431), we get a palindrome (168802208861).

Subtracting from 134401104430 its reverse (34401104431), we obtain a palindrome (99999999999).

The spelling of 134401104430 in words is "one hundred thirty-four billion, four hundred one million, one hundred four thousand, four hundred thirty".

Divisors: 1 2 5 10 157 314 785 1570 85605799 171211598 428028995 856057990 13440110443 26880220886 67200552215 134401104430