13440114300 has 72 divisors (see below), whose sum is σ = 38918950000. Its totient is φ = 3581061120.

The previous prime is 13440114299. The next prime is 13440114301. The reversal of 13440114300 is 341104431.

It is an interprime number because it is at equal distance from previous prime (13440114299) and next prime (13440114301).

It is a super-3 number, since 3×13440114300³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440114301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 356766 + ... + 392634.

Almost surely, 2^13440114300 is an apocalyptic number.

13440114300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13440114300 is an abundant number, since it is smaller than the sum of its proper divisors (25478835700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13440114300 is a wasteful number, since it uses less digits than its factorization.

13440114300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37135 (or 37128 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13440114300 its reverse (341104431), we get a palindrome (13781218731).

The spelling of 13440114300 in words is "thirteen billion, four hundred forty million, one hundred fourteen thousand, three hundred".