Search a number
-
+
134423401367 is a prime number
BaseRepresentation
bin111110100110001000…
…0100101001110010111
3110211222012100022120002
41331030100211032113
54200244342320432
6141430412001515
712466065026153
oct1751420451627
9424865308502
10134423401367
1152010562042
122207616029b
13c8a343c1a8
146712b56063
15376b370e62
hex1f4c425397

134423401367 has 2 divisors, whose sum is σ = 134423401368. Its totient is φ = 134423401366.

The previous prime is 134423401319. The next prime is 134423401369. The reversal of 134423401367 is 763104324431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134423401367 - 224 = 134406624151 is a prime.

Together with 134423401369, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134423401367.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134423401369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67211700683 + 67211700684.

It is an arithmetic number, because the mean of its divisors is an integer number (67211700684).

Almost surely, 2134423401367 is an apocalyptic number.

134423401367 is a deficient number, since it is larger than the sum of its proper divisors (1).

134423401367 is an equidigital number, since it uses as much as digits as its factorization.

134423401367 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 38.

Adding to 134423401367 its reverse (763104324431), we get a palindrome (897527725798).

The spelling of 134423401367 in words is "one hundred thirty-four billion, four hundred twenty-three million, four hundred one thousand, three hundred sixty-seven".