Base | Representation |
---|---|
bin | 111110100110001000… |
… | …0100101001110010111 |
3 | 110211222012100022120002 |
4 | 1331030100211032113 |
5 | 4200244342320432 |
6 | 141430412001515 |
7 | 12466065026153 |
oct | 1751420451627 |
9 | 424865308502 |
10 | 134423401367 |
11 | 52010562042 |
12 | 2207616029b |
13 | c8a343c1a8 |
14 | 6712b56063 |
15 | 376b370e62 |
hex | 1f4c425397 |
134423401367 has 2 divisors, whose sum is σ = 134423401368. Its totient is φ = 134423401366.
The previous prime is 134423401319. The next prime is 134423401369. The reversal of 134423401367 is 763104324431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134423401367 - 224 = 134406624151 is a prime.
Together with 134423401369, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134423401367.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134423401369) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67211700683 + 67211700684.
It is an arithmetic number, because the mean of its divisors is an integer number (67211700684).
Almost surely, 2134423401367 is an apocalyptic number.
134423401367 is a deficient number, since it is larger than the sum of its proper divisors (1).
134423401367 is an equidigital number, since it uses as much as digits as its factorization.
134423401367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 134423401367 its reverse (763104324431), we get a palindrome (897527725798).
The spelling of 134423401367 in words is "one hundred thirty-four billion, four hundred twenty-three million, four hundred one thousand, three hundred sixty-seven".
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