1344311130 has 64 divisors (see below), whose sum is σ = 3391435008. Its totient is φ = 340369920.

The previous prime is 1344311119. The next prime is 1344311131. The reversal of 1344311130 is 311134431.

It is a junction number, because it is equal to n+sod(n) for n = 1344311097 and 1344311106.

It is not an unprimeable number, because it can be changed into a prime (1344311131) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 87420 + ... + 101640.

It is an arithmetic number, because the mean of its divisors is an integer number (52991172).

Almost surely, 2^1344311130 is an apocalyptic number.

1344311130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1344311130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1695717504).

1344311130 is an abundant number, since it is smaller than the sum of its proper divisors (2047123878).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1344311130 is a wasteful number, since it uses less digits than its factorization.

1344311130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14391.

The product of its (nonzero) digits is 432, while the sum is 21.

The square root of 1344311130 is about 36664.8486973559. The cubic root of 1344311130 is about 1103.6548211328.

Adding to 1344311130 its reverse (311134431), we get a palindrome (1655445561).

The spelling of 1344311130 in words is "one billion, three hundred forty-four million, three hundred eleven thousand, one hundred thirty".