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134432144041043 is a prime number
BaseRepresentation
bin11110100100001111101100…
…001100010010010001010011
3122121222120212020221211110102
4132210033230030102101103
5120110014012333303133
61153525135134323015
740213254564360152
oct3644175414222123
9577876766854412
10134432144041043
113991a396743a72
12130b1a2505946b
135a01b87321b84
14252a79c77b599
151081d4dddc7e8
hex7a43ec312453

134432144041043 has 2 divisors, whose sum is σ = 134432144041044. Its totient is φ = 134432144041042.

The previous prime is 134432144040973. The next prime is 134432144041081. The reversal of 134432144041043 is 340140441234431.

It is a happy number.

It is an a-pointer prime, because the next prime (134432144041081) can be obtained adding 134432144041043 to its sum of digits (38).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134432144041043 - 28 = 134432144040787 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134432144040988 and 134432144041006.

It is not a weakly prime, because it can be changed into another prime (134432144049043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67216072020521 + 67216072020522.

It is an arithmetic number, because the mean of its divisors is an integer number (67216072020522).

Almost surely, 2134432144041043 is an apocalyptic number.

134432144041043 is a deficient number, since it is larger than the sum of its proper divisors (1).

134432144041043 is an equidigital number, since it uses as much as digits as its factorization.

134432144041043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 221184, while the sum is 38.

Adding to 134432144041043 its reverse (340140441234431), we get a palindrome (474572585275474).

The spelling of 134432144041043 in words is "one hundred thirty-four trillion, four hundred thirty-two billion, one hundred forty-four million, forty-one thousand, forty-three".