13443244340 has 48 divisors (see below), whose sum is σ = 28364590800. Its totient is φ = 5351869440.

The previous prime is 13443244313. The next prime is 13443244349. The reversal of 13443244340 is 4344234431.

It can be written as a sum of positive squares in 8 ways, for example, as 99760144 + 13343484196 = 9988^2 + 115514^2 .

It is a super-3 number, since 3×13443244340³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13443244297 and 13443244306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13443244349) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8677886 + ... + 8679434.

It is an arithmetic number, because the mean of its divisors is an integer number (590928975).

Almost surely, 2^13443244340 is an apocalyptic number.

13443244340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13443244340 is an abundant number, since it is smaller than the sum of its proper divisors (14921346460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13443244340 is a wasteful number, since it uses less digits than its factorization.

13443244340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3332 (or 3330 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 32.

Adding to 13443244340 its reverse (4344234431), we get a palindrome (17787478771).

Subtracting from 13443244340 its reverse (4344234431), we obtain a palindrome (9099009909).

The spelling of 13443244340 in words is "thirteen billion, four hundred forty-three million, two hundred forty-four thousand, three hundred forty".