Base | Representation |
---|---|
bin | 10011100100000100100… |
… | …011100101111110100111 |
3 | 11202112010122001021101021 |
4 | 103210010203211332213 |
5 | 134011313201444421 |
6 | 2505335343312011 |
7 | 166062341451211 |
oct | 23440443457647 |
9 | 4675118037337 |
10 | 1344401203111 |
11 | 47918048127a |
12 | 1986792ab607 |
13 | 99a12c414a5 |
14 | 490d84a55b1 |
15 | 24e86ed2341 |
hex | 139048e5fa7 |
1344401203111 has 2 divisors, whose sum is σ = 1344401203112. Its totient is φ = 1344401203110.
The previous prime is 1344401203109. The next prime is 1344401203151. The reversal of 1344401203111 is 1113021044431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1344401203111 - 21 = 1344401203109 is a prime.
Together with 1344401203109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344401203151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672200601555 + 672200601556.
It is an arithmetic number, because the mean of its divisors is an integer number (672200601556).
Almost surely, 21344401203111 is an apocalyptic number.
1344401203111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344401203111 is an equidigital number, since it uses as much as digits as its factorization.
1344401203111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1344401203111 its reverse (1113021044431), we get a palindrome (2457422247542).
The spelling of 1344401203111 in words is "one trillion, three hundred forty-four billion, four hundred one million, two hundred three thousand, one hundred eleven".
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