Base | Representation |
---|---|
bin | 1100001110100010111100… |
… | …1111111110101010010010 |
3 | 1202121020102021202201010012 |
4 | 3003220233033332222102 |
5 | 3230231343312320300 |
6 | 44332035030234522 |
7 | 2555204565342266 |
oct | 303505717765222 |
9 | 52536367681105 |
10 | 13444040354450 |
11 | 4313649327242 |
12 | 1611665ab5a42 |
13 | 7669c9459694 |
14 | 3469a32120a6 |
15 | 184a9c60e435 |
hex | c3a2f3fea92 |
13444040354450 has 96 divisors (see below), whose sum is σ = 25176280222080. Its totient is φ = 5341150886400.
The previous prime is 13444040354449. The next prime is 13444040354509. The reversal of 13444040354450 is 5445304044431.
It is a junction number, because it is equal to n+sod(n) for n = 13444040354398 and 13444040354407.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5332819190 + ... + 5332821710.
It is an arithmetic number, because the mean of its divisors is an integer number (262252918980).
Almost surely, 213444040354450 is an apocalyptic number.
13444040354450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13444040354450 is a deficient number, since it is larger than the sum of its proper divisors (11732239867630).
13444040354450 is a wasteful number, since it uses less digits than its factorization.
13444040354450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3972 (or 3967 counting only the distinct ones).
The product of its (nonzero) digits is 921600, while the sum is 41.
Adding to 13444040354450 its reverse (5445304044431), we get a palindrome (18889344398881).
The spelling of 13444040354450 in words is "thirteen trillion, four hundred forty-four billion, forty million, three hundred fifty-four thousand, four hundred fifty".
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