Base | Representation |
---|---|
bin | 111110101000011010… |
… | …1011001101111101111 |
3 | 110212011112210012002121 |
4 | 1331100311121233233 |
5 | 4200424020200133 |
6 | 141442153133411 |
7 | 12501016342525 |
oct | 1752065315757 |
9 | 425145705077 |
10 | 134500162543 |
11 | 5204a92092a |
12 | 220979ba267 |
13 | c8b63072c6 |
14 | 671d018315 |
15 | 3772e8502d |
hex | 1f50d59bef |
134500162543 has 2 divisors, whose sum is σ = 134500162544. Its totient is φ = 134500162542.
The previous prime is 134500162541. The next prime is 134500162549. The reversal of 134500162543 is 345261005431.
It is a weak prime.
It is an emirp because it is prime and its reverse (345261005431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134500162543 - 21 = 134500162541 is a prime.
Together with 134500162541, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 134500162499 and 134500162508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134500162541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67250081271 + 67250081272.
It is an arithmetic number, because the mean of its divisors is an integer number (67250081272).
Almost surely, 2134500162543 is an apocalyptic number.
134500162543 is a deficient number, since it is larger than the sum of its proper divisors (1).
134500162543 is an equidigital number, since it uses as much as digits as its factorization.
134500162543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 134500162543 its reverse (345261005431), we get a palindrome (479761167974).
The spelling of 134500162543 in words is "one hundred thirty-four billion, five hundred million, one hundred sixty-two thousand, five hundred forty-three".
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