Base | Representation |
---|---|
bin | 1100001110111011011110… |
… | …0001110110111011011000 |
3 | 1202121212101221202012201221 |
4 | 3003232313201312323120 |
5 | 3230333333124210130 |
6 | 44335044051421424 |
7 | 2555526642055024 |
oct | 303566741667330 |
9 | 52555357665657 |
10 | 13450621710040 |
11 | 4316416331099 |
12 | 16129a1bb4874 |
13 | 767507ac3928 |
14 | 347029313384 |
15 | 184d352d087a |
hex | c3bb7876ed8 |
13450621710040 has 32 divisors (see below), whose sum is σ = 30278829419280. Its totient is φ = 5377594360192.
The previous prime is 13450621710023. The next prime is 13450621710047. The reversal of 13450621710040 is 4001712605431.
It is a junction number, because it is equal to n+sod(n) for n = 13450621709978 and 13450621710005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13450621710047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82865527 + ... + 83027686.
Almost surely, 213450621710040 is an apocalyptic number.
13450621710040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13450621710040 is an abundant number, since it is smaller than the sum of its proper divisors (16828207709240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13450621710040 is a wasteful number, since it uses less digits than its factorization.
13450621710040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165895251 (or 165895247 counting only the distinct ones).
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 13450621710040 in words is "thirteen trillion, four hundred fifty billion, six hundred twenty-one million, seven hundred ten thousand, forty".
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