Base | Representation |
---|---|
bin | 111110101000101110… |
… | …0011101101111000100 |
3 | 110212012021001102200021 |
4 | 1331101130131233010 |
5 | 4200434130340000 |
6 | 141443200424524 |
7 | 12501202361605 |
oct | 1752134355704 |
9 | 425167042607 |
10 | 134510402500 |
11 | 52055685301 |
12 | 2209b318144 |
13 | c8b8481156 |
14 | 6720521dac |
15 | 3773d0911a |
hex | 1f5171dbc4 |
134510402500 has 30 divisors (see below), whose sum is σ = 294147353654. Its totient is φ = 53804160000.
The previous prime is 134510402461. The next prime is 134510402501. The reversal of 134510402500 is 5204015431.
It is a happy number.
It can be written as a sum of positive squares in 5 ways, for example, as 10983459204 + 123526943296 = 104802^2 + 351464^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (134510402501) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 26899581 + ... + 26904580.
Almost surely, 2134510402500 is an apocalyptic number.
134510402500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134510402500 is an abundant number, since it is smaller than the sum of its proper divisors (159636951154).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134510402500 is an equidigital number, since it uses as much as digits as its factorization.
134510402500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53804185 (or 53804168 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 134510402500 its reverse (5204015431), we get a palindrome (139714417931).
The spelling of 134510402500 in words is "one hundred thirty-four billion, five hundred ten million, four hundred two thousand, five hundred".
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