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13457720117 is a prime number
BaseRepresentation
bin11001000100010010…
…01000001100110101
31021201220002000102102
430202021020030311
5210030134020432
610103221351445
7654331506422
oct144211101465
937656060372
1013457720117
115786594346
122736b68585
1313661725ca
14919476d49
1553b717962
hex322248335

13457720117 has 2 divisors, whose sum is σ = 13457720118. Its totient is φ = 13457720116.

The previous prime is 13457720069. The next prime is 13457720119. The reversal of 13457720117 is 71102775431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9508980196 + 3948739921 = 97514^2 + 62839^2 .

It is a cyclic number.

It is not a de Polignac number, because 13457720117 - 28 = 13457719861 is a prime.

It is a super-2 number, since 2×134577201172 (a number of 21 digits) contains 22 as substring.

Together with 13457720119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13457720119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6728860058 + 6728860059.

It is an arithmetic number, because the mean of its divisors is an integer number (6728860059).

Almost surely, 213457720117 is an apocalyptic number.

It is an amenable number.

13457720117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13457720117 is an equidigital number, since it uses as much as digits as its factorization.

13457720117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41160, while the sum is 38.

The spelling of 13457720117 in words is "thirteen billion, four hundred fifty-seven million, seven hundred twenty thousand, one hundred seventeen".