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13460078111 is a prime number
BaseRepresentation
bin11001000100100100…
…00111111000011111
31021202001111210222112
430202102013320133
5210031234444421
610103344104235
7654360530144
oct144222077037
937661453875
1013460078111
1157879549a7
12273790507b
1313667b997c
149198cc3cb
1553ba3145b
hex322487e1f

13460078111 has 2 divisors, whose sum is σ = 13460078112. Its totient is φ = 13460078110.

The previous prime is 13460078057. The next prime is 13460078113. The reversal of 13460078111 is 11187006431.

13460078111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11187006431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13460078111 is a prime.

Together with 13460078113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13460078113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6730039055 + 6730039056.

It is an arithmetic number, because the mean of its divisors is an integer number (6730039056).

Almost surely, 213460078111 is an apocalyptic number.

13460078111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13460078111 is an equidigital number, since it uses as much as digits as its factorization.

13460078111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 32.

The spelling of 13460078111 in words is "thirteen billion, four hundred sixty million, seventy-eight thousand, one hundred eleven".