Base | Representation |
---|---|
bin | 111110101101000100… |
… | …1111111010101100101 |
3 | 110212120110001201022102 |
4 | 1331122021333111211 |
5 | 4201234034214331 |
6 | 141505501141445 |
7 | 12504625553351 |
oct | 1753211772545 |
9 | 425513051272 |
10 | 134656554341 |
11 | 52120129351 |
12 | 2212025a885 |
13 | c90c83362a |
14 | 6735ac8461 |
15 | 3781a784cb |
hex | 1f5a27f565 |
134656554341 has 2 divisors, whose sum is σ = 134656554342. Its totient is φ = 134656554340.
The previous prime is 134656554313. The next prime is 134656554343. The reversal of 134656554341 is 143455656431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102563265025 + 32093289316 = 320255^2 + 179146^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134656554341 is a prime.
Together with 134656554343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134656554343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67328277170 + 67328277171.
It is an arithmetic number, because the mean of its divisors is an integer number (67328277171).
Almost surely, 2134656554341 is an apocalyptic number.
It is an amenable number.
134656554341 is a deficient number, since it is larger than the sum of its proper divisors (1).
134656554341 is an equidigital number, since it uses as much as digits as its factorization.
134656554341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592000, while the sum is 47.
The spelling of 134656554341 in words is "one hundred thirty-four billion, six hundred fifty-six million, five hundred fifty-four thousand, three hundred forty-one".
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