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1348026149 is a prime number
BaseRepresentation
bin101000001011001…
…0011111100100101
310110221112211020102
41100112103330211
510230043314044
6341432513445
745256014251
oct12026237445
93427484212
101348026149
11631a1aaa8
1231754b885
13186381b12
14cb063261
157d52a24e
hex50593f25

1348026149 has 2 divisors, whose sum is σ = 1348026150. Its totient is φ = 1348026148.

The previous prime is 1348026091. The next prime is 1348026151. The reversal of 1348026149 is 9416208431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1221013249 + 127012900 = 34943^2 + 11270^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1348026149 is a prime.

Together with 1348026151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1348026179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674013074 + 674013075.

It is an arithmetic number, because the mean of its divisors is an integer number (674013075).

Almost surely, 21348026149 is an apocalyptic number.

It is an amenable number.

1348026149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1348026149 is an equidigital number, since it uses as much as digits as its factorization.

1348026149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The square root of 1348026149 is about 36715.4756063434. The cubic root of 1348026149 is about 1104.6705402465.

The spelling of 1348026149 in words is "one billion, three hundred forty-eight million, twenty-six thousand, one hundred forty-nine".