134905543 has 2 divisors, whose sum is σ = 134905544. Its totient is φ = 134905542.

The previous prime is 134905541. The next prime is 134905553. The reversal of 134905543 is 345509431.

134905543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134905543 - 2¹ = 134905541 is a prime.

Together with 134905541, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 134905499 and 134905508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134905541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67452771 + 67452772.

It is an arithmetic number, because the mean of its divisors is an integer number (67452772).

Almost surely, 2^134905543 is an apocalyptic number.

134905543 is a deficient number, since it is larger than the sum of its proper divisors (1).

134905543 is an equidigital number, since it uses as much as digits as its factorization.

134905543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 34.

The square root of 134905543 is about 11614.8845452721. The cubic root of 134905543 is about 512.8731122376.

The spelling of 134905543 in words is "one hundred thirty-four million, nine hundred five thousand, five hundred forty-three".