Base | Representation |
---|---|
bin | 111110110100100010… |
… | …0010100111100110111 |
3 | 110220012212210212101122 |
4 | 1331221010110330313 |
5 | 4202242110300442 |
6 | 141550355214155 |
7 | 12514054161344 |
oct | 1755104247467 |
9 | 426185725348 |
10 | 134906728247 |
11 | 52239370745 |
12 | 2218bba735b |
13 | c94c607225 |
14 | 675b00b7cb |
15 | 37989e3dd2 |
hex | 1f69114f37 |
134906728247 has 2 divisors, whose sum is σ = 134906728248. Its totient is φ = 134906728246.
The previous prime is 134906728199. The next prime is 134906728273. The reversal of 134906728247 is 742827609431.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (742827609431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134906728247 is a prime.
It is a super-3 number, since 3×1349067282473 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134906728277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67453364123 + 67453364124.
It is an arithmetic number, because the mean of its divisors is an integer number (67453364124).
Almost surely, 2134906728247 is an apocalyptic number.
134906728247 is a deficient number, since it is larger than the sum of its proper divisors (1).
134906728247 is an equidigital number, since it uses as much as digits as its factorization.
134906728247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4064256, while the sum is 53.
The spelling of 134906728247 in words is "one hundred thirty-four billion, nine hundred six million, seven hundred twenty-eight thousand, two hundred forty-seven".
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