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13491295189 is a prime number
BaseRepresentation
bin11001001000010010…
…01101001111010101
31021211020020210202121
430210021031033111
5210112232421224
610110421135541
7655220055061
oct144411151725
937736223677
1013491295189
1157a3536839
12274625a5b1
1313700c9908
1491dad6aa1
1553e64abe4
hex32424d3d5

13491295189 has 2 divisors, whose sum is σ = 13491295190. Its totient is φ = 13491295188.

The previous prime is 13491295187. The next prime is 13491295241. The reversal of 13491295189 is 98159219431.

It is an a-pointer prime, because the next prime (13491295241) can be obtained adding 13491295189 to its sum of digits (52).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13413114225 + 78180964 = 115815^2 + 8842^2 .

It is a cyclic number.

It is not a de Polignac number, because 13491295189 - 21 = 13491295187 is a prime.

Together with 13491295187, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13491295187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6745647594 + 6745647595.

It is an arithmetic number, because the mean of its divisors is an integer number (6745647595).

Almost surely, 213491295189 is an apocalyptic number.

It is an amenable number.

13491295189 is a deficient number, since it is larger than the sum of its proper divisors (1).

13491295189 is an equidigital number, since it uses as much as digits as its factorization.

13491295189 is an evil number, because the sum of its binary digits is even.

The product of its digits is 699840, while the sum is 52.

The spelling of 13491295189 in words is "thirteen billion, four hundred ninety-one million, two hundred ninety-five thousand, one hundred eighty-nine".