Base | Representation |
---|---|
bin | 11110101100111000001010… |
… | …010100101010011001011110 |
3 | 122201002022001011002220210112 |
4 | 132230320022110222121132 |
5 | 120144223411342242400 |
6 | 1155101443005010022 |
7 | 40304155112564225 |
oct | 3654701224523136 |
9 | 581068034086715 |
10 | 135025355040350 |
11 | 3a028a278a8895 |
12 | 1318899a253912 |
13 | 5a45ab45b20b8 |
14 | 254b39510bcbc |
15 | 10924bcc1e835 |
hex | 7ace0a52a65e |
135025355040350 has 48 divisors (see below), whose sum is σ = 277482284648928. Its totient is φ = 48622941143040.
The previous prime is 135025355040337. The next prime is 135025355040361. The reversal of 135025355040350 is 53040553520531.
It is a junction number, because it is equal to n+sod(n) for n = 135025355040298 and 135025355040307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3453314339 + ... + 3453353438.
It is an arithmetic number, because the mean of its divisors is an integer number (5780880930186).
Almost surely, 2135025355040350 is an apocalyptic number.
135025355040350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135025355040350 is an abundant number, since it is smaller than the sum of its proper divisors (142456929608578).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135025355040350 is a wasteful number, since it uses less digits than its factorization.
135025355040350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6906667829 (or 6906667824 counting only the distinct ones).
The product of its (nonzero) digits is 675000, while the sum is 41.
The spelling of 135025355040350 in words is "one hundred thirty-five trillion, twenty-five billion, three hundred fifty-five million, forty thousand, three hundred fifty".
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