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1350414055559 is a prime number
BaseRepresentation
bin10011101001101010111…
…100110011100010000111
311210002122200021211022002
4103221222330303202013
5134111121444234214
62512212135455515
7166364343036242
oct23515274634207
94702580254262
101350414055559
11480786590318
12199876b2759b
139a46088a24a
1449508c9c259
15251d9d081de
hex13a6af33887

1350414055559 has 2 divisors, whose sum is σ = 1350414055560. Its totient is φ = 1350414055558.

The previous prime is 1350414055517. The next prime is 1350414055561. The reversal of 1350414055559 is 9555504140531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350414055559 is a prime.

Together with 1350414055561, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350414051559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675207027779 + 675207027780.

It is an arithmetic number, because the mean of its divisors is an integer number (675207027780).

Almost surely, 21350414055559 is an apocalyptic number.

1350414055559 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350414055559 is an equidigital number, since it uses as much as digits as its factorization.

1350414055559 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350000, while the sum is 47.

The spelling of 1350414055559 in words is "one trillion, three hundred fifty billion, four hundred fourteen million, fifty-five thousand, five hundred fifty-nine".