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1350552656773 is a prime number
BaseRepresentation
bin10011101001110011001…
…101100001101110000101
311210010000100002111102101
4103221303031201232011
5134111412440004043
62512234010312101
7166400645112355
oct23516315415605
94703010074371
101350552656773
11480847847481
121998b5428631
139a4834c79b8
144951d45ab65
15251e708524d
hex13a73361b85

1350552656773 has 2 divisors, whose sum is σ = 1350552656774. Its totient is φ = 1350552656772.

The previous prime is 1350552656771. The next prime is 1350552656777. The reversal of 1350552656773 is 3776562550531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 770248459044 + 580304197729 = 877638^2 + 761777^2 .

It is an emirp because it is prime and its reverse (3776562550531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1350552656773 - 21 = 1350552656771 is a prime.

Together with 1350552656771, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350552656771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675276328386 + 675276328387.

It is an arithmetic number, because the mean of its divisors is an integer number (675276328387).

Almost surely, 21350552656773 is an apocalyptic number.

It is an amenable number.

1350552656773 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350552656773 is an equidigital number, since it uses as much as digits as its factorization.

1350552656773 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19845000, while the sum is 55.

The spelling of 1350552656773 in words is "one trillion, three hundred fifty billion, five hundred fifty-two million, six hundred fifty-six thousand, seven hundred seventy-three".