Base | Representation |
---|---|
bin | 10011101001110111010… |
… | …111111110001001111111 |
3 | 11210010012012112002012002 |
4 | 103221313113332021333 |
5 | 134112033330103201 |
6 | 2512244543332515 |
7 | 166402453600316 |
oct | 23516727761177 |
9 | 4703165462162 |
10 | 1350622503551 |
11 | 480883213392 |
12 | 1999148b113b |
13 | 9a494b11859 |
14 | 4952883d27d |
15 | 251ed28076b |
hex | 13a775fe27f |
1350622503551 has 2 divisors, whose sum is σ = 1350622503552. Its totient is φ = 1350622503550.
The previous prime is 1350622503547. The next prime is 1350622503553. The reversal of 1350622503551 is 1553052260531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350622503551 - 22 = 1350622503547 is a prime.
It is a super-2 number, since 2×13506225035512 (a number of 25 digits) contains 22 as substring.
Together with 1350622503553, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350622503553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675311251775 + 675311251776.
It is an arithmetic number, because the mean of its divisors is an integer number (675311251776).
Almost surely, 21350622503551 is an apocalyptic number.
1350622503551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350622503551 is an equidigital number, since it uses as much as digits as its factorization.
1350622503551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 1350622503551 in words is "one trillion, three hundred fifty billion, six hundred twenty-two million, five hundred three thousand, five hundred fifty-one".
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