Base | Representation |
---|---|
bin | 11110101110000001101000… |
… | …011100011101011100000010 |
3 | 122201100211200000202122020020 |
4 | 132232001220130131130002 |
5 | 120202021442322212200 |
6 | 1155202011015354310 |
7 | 40312650050103051 |
oct | 3656015034353402 |
9 | 581324600678206 |
10 | 135104243554050 |
11 | 3a05942a364851 |
12 | 131a0135982996 |
13 | 5a50377373cc4 |
14 | 255111a3d8398 |
15 | 1094588838ea0 |
hex | 7ae06871d702 |
135104243554050 has 24 divisors (see below), whose sum is σ = 335058524014416. Its totient is φ = 36027798281040.
The previous prime is 135104243554031. The next prime is 135104243554127. The reversal of 135104243554050 is 50455342401531.
It is a junction number, because it is equal to n+sod(n) for n = 135104243553993 and 135104243554011.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 450347478364 + ... + 450347478663.
It is an arithmetic number, because the mean of its divisors is an integer number (13960771833934).
Almost surely, 2135104243554050 is an apocalyptic number.
135104243554050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135104243554050 is an abundant number, since it is smaller than the sum of its proper divisors (199954280460366).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135104243554050 is a wasteful number, since it uses less digits than its factorization.
135104243554050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 900694957042 (or 900694957037 counting only the distinct ones).
The product of its (nonzero) digits is 720000, while the sum is 42.
Adding to 135104243554050 its reverse (50455342401531), we get a palindrome (185559585955581).
The spelling of 135104243554050 in words is "one hundred thirty-five trillion, one hundred four billion, two hundred forty-three million, five hundred fifty-four thousand, fifty".
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