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135163891349 is a prime number
BaseRepresentation
bin111110111100001100…
…1010100111010010101
3110220212210201002211222
41331320121110322111
54203303424010344
6142032103140125
712523326056114
oct1757031247225
9426783632758
10135163891349
1152360547133
1222242144645
13c990987146
14678322dc7b
1537b13905ee
hex1f78654e95

135163891349 has 2 divisors, whose sum is σ = 135163891350. Its totient is φ = 135163891348.

The previous prime is 135163891327. The next prime is 135163891351. The reversal of 135163891349 is 943198361531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125444889124 + 9719002225 = 354182^2 + 98585^2 .

It is a cyclic number.

It is not a de Polignac number, because 135163891349 - 212 = 135163887253 is a prime.

Together with 135163891351, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135163891349.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135163891549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67581945674 + 67581945675.

It is an arithmetic number, because the mean of its divisors is an integer number (67581945675).

Almost surely, 2135163891349 is an apocalyptic number.

It is an amenable number.

135163891349 is a deficient number, since it is larger than the sum of its proper divisors (1).

135163891349 is an equidigital number, since it uses as much as digits as its factorization.

135163891349 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2099520, while the sum is 53.

The spelling of 135163891349 in words is "one hundred thirty-five billion, one hundred sixty-three million, eight hundred ninety-one thousand, three hundred forty-nine".