1352434742350 has 48 divisors (see below), whose sum is σ = 2559755133936. Its totient is φ = 531483552000.

The previous prime is 1352434742341. The next prime is 1352434742353. The reversal of 1352434742350 is 532474342531.

It is a super-3 number, since 3×1352434742350³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1352434742297 and 1352434742306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1352434742353) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2355145 + ... + 2872555.

It is an arithmetic number, because the mean of its divisors is an integer number (53328231957).

Almost surely, 2^{1352434742350} is an apocalyptic number.

1352434742350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1352434742350 is a deficient number, since it is larger than the sum of its proper divisors (1207320391586).

1352434742350 is a wasteful number, since it uses less digits than its factorization.

1352434742350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 518341 (or 518336 counting only the distinct ones).

The product of its (nonzero) digits is 1209600, while the sum is 43.

The spelling of 1352434742350 in words is "one trillion, three hundred fifty-two billion, four hundred thirty-four million, seven hundred forty-two thousand, three hundred fifty".